256t^2-324=0

Solution for 256t^2-324=0 equation:

256t^2-324=0

a = 256; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·256·(-324)
Δ = 331776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{331776}=576$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-576}{2*256}=\frac{-576}{512}
=-1+1/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+576}{2*256}=\frac{576}{512}
=1+1/8
$